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In probability theory and , a Markov operator is an operator on a certain that conserves the mass (the so-called Markov property). If the underlying is topologically sufficiently rich enough, then the Markov operator admits a kernel representation. Markov operators can be or non-linear. Closely related to Markov operators is the Markov semigroup.

The definition of Markov operators is not entirely consistent in the literature. Markov operators are named after the Russian mathematician .


Definitions

Markov operator
Let (E,\mathcal{F}) be a and V a set of real, measurable functions f:(E,\mathcal{F})\to (\mathbb{R},\mathcal{B}(\mathbb{R})).

A linear operator P on V is a Markov operator if the following is true

  1. P maps bounded, measurable function on bounded, measurable functions.
  2. Let \mathbf{1} be the constant function x\mapsto 1, then P(\mathbf{1})=\mathbf{1} holds. ( conservation of mass / Markov property)
  3. If f\geq 0 then Pf\geq 0. ( conservation of positivity)


Alternative definitions
Some authors define the operators on the as P:L^p(X)\to L^p(Y) and replace the first condition (bounded, measurable functions on such) with the property
\|Pf\|_Y = \|f\|_X,\quad \forall f\in L^p(X)


Markov semigroup
Let \mathcal{P}=\{P_t\}_{t\geq 0} be a family of Markov operators defined on the set of bounded, measurables function on (E,\mathcal{F}). Then \mathcal{P} is a Markov semigroup when the following is true
  1. P_0=\operatorname{Id}.
  2. P_{t+s}=P_t\circ P_s for all t,s\geq 0.
  3. There exist a σ-finite measure \mu on (E,\mathcal{F}) that is invariant under \mathcal{P}, that means for all bounded, positive and measurable functions f:E\to \mathbb{R} and every t\geq 0 the following holds
::\int_E P_tf\mathrm{d}\mu =\int_E f\mathrm{d}\mu.


Dual semigroup
Each Markov semigroup \mathcal{P}=\{P_t\}_{t\geq 0} induces a dual semigroup (P^*_t)_{t\geq 0} through
\int_EP_tf\mathrm{d\mu} =\int_E f\mathrm{d}\left(P^*_t\mu\right).
If \mu is invariant under \mathcal{P} then P^*_t\mu=\mu.


Infinitesimal generator of the semigroup
Let \{P_t\}_{t\geq 0} be a family of bounded, linear Markov operators on the L^2(\mu), where \mu is an invariant measure. The infinitesimal generator L of the Markov semigroup \mathcal{P}=\{P_t\}_{t\geq 0} is defined as
Lf=\lim\limits_{t\downarrow 0}\frac{P_t f-f}{t},
and the domain D(L) is the L^2(\mu)-space of all such functions where this limit exists and is in L^2(\mu) again.
D(L)=\left\{f\in L^2(\mu): \lim\limits_{t\downarrow 0}\frac{P_t f-f}{t}\text{ exists and is in } L^2(\mu)\right\}.

The carré du champ operator \Gamma measures how far L is from being a derivation.


Kernel representation of a Markov operator
A Markov operator P_t has a kernel representation
(P_tf)(x)=\int_E f(y)p_t(x,\mathrm{d}y),\quad x\in E,
with respect to some probability kernel p_t(x,A), if the underlying measurable space (E,\mathcal{F}) has the following sufficient topological properties:
  1. Each probability measure \mu:\mathcal{F}\times \mathcal{F}\to 0,1 can be decomposed as \mu(\mathrm{d}x,\mathrm{d}y)=k(x,\mathrm{d}y)\mu_1(\mathrm{d}x), where \mu_1 is the projection onto the first component and k(x,\mathrm{d}y) is a probability kernel.
  2. There exist a countable family that generates the σ-algebra \mathcal{F}.
If one defines now a σ-finite measure on (E,\mathcal{F}) then it is possible to prove that ever Markov operator P admits such a kernel representation with respect to k(x,\mathrm{d}y).


Literature

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